Homework Answers
mass of the new gas = 0.1552 g
pressure = 17.20 mmHg = 0.02263 atm
volume = 1850.0 ml = 1.850 L
Temperature = 21.00 C = 294 K
a.) we know that ideal gas equation, PV = nRT
or PV = (m/M)RT
M= mRT/PV
molar mass of the gas = (0.1552*0.0821*294)/(0.02263*1.850) = 89.48 g/mol.
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so, identity of the gas is it's molar mass that is 89.48 g/mol.
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