μ = 18.2
σ = 2.3
z = x - μ / σ
A)
P( 16 < X < 20)
= P(16 - 18.2/2.3 < Z < 20-18.2/2.3 )
= P(-0.96 < Z < 0.78)
= 0.3315 + 0.2823 [STANDARD NORMAL DISTRIBUTION TABLE]
= 0.6138
B)
Unacceptable sweetpeas probabality
=P(X < 14) + P(X >24)
= P(Z < 14 - 18.2/2.3) + P(Z > 24-18.2/2.3)
= P(Z < -1.83) + P(Z > 2.52)
= (0.5-0.4664) + (0.5-0.4941)
= 0.0395
Number of sweetpeas are unacceptable
= 500 x 0.0395
= 19.75
=20
the b one The length of sweet pea flower stems are normally distributed with mean 18.2 cm and standard deviation 2.3...
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