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Question 2 Status: Answer saved | Points possible: 1.00 Consider the balanced reaction of magnesium and oxygen. 2 Mg + O2 + 2

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my of O2 3 1.39 gm Mg = 139 = 0.058 more of 2.8 gon O2 = 218 = 0.086 mole 2 mg + O2 – 2 ngo 2x0.029 0.029 . 240.029 - 0.058 mmy of O2 3 1.39 gm Mg = 139 = 0.058 more of 2.8 gon O2 = 218 = 0.086 mole 2 mg + O2 – 2 ngo 2x0.029 0.029 . 240.029 - 0.058 m

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