Homework Answers
Kw = [H+][OH-]
Since H2O is neutral, [OH-] = [H+]
So,
Kw = [H+][H+]
Kw = [H+]^2
1.87*10^-15 = [H+]^2
[H+] = 4.32*10^-8 M
use:
pH = -log [H+]
= -log (4.32*10^-8)
= 7.36
Answer: 7.36
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8. Determine the reduction potential for H2O(l) in neutral water: [H"]= [OH = 10? (6 points) (P. = 1 atm) 9. A cobalt electrode is placed in 1.00 L of I M CO(NO3)2(aq) and a chromium electrode is placed in 1.00 L of IM Cr(NO3)3(aq). Electrodes are connected by a wire through a voltmeter and the solutions are connected by a salt bridge. (16 points) a. The reduction reaction will be: b. The oxidation reaction will be: c. The...
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