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1) Using a 0.25 M phosphate buffer with a pH of 7.2, you add 0.79 mL of 0.48 M HCl to 54 mL of the buffer. What is the n...

1) Using a 0.25 M phosphate buffer with a pH of 7.2, you add 0.79 mL of 0.48 M HCl to 54 mL of the buffer. What is the new pH of the solution? (Enter your answer to three significant figures.) 2) Using a 0.25 M phosphate buffer with a pH of 7.2, you add 0.79 mL of 0.48 M NaOH to 54 mL of the buffer. What is the new pH of the solution? (Enter your answer to three significant figures.)

pKa value = 7.21

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Answer #1

The phosphate buffer must be prepared by H2PO41 and HPO4 2 [base] pH - pК, +1og [acid] [НРО, ] [Н, РО, ] 7.2 7.21+log HPO log

(a) Number of moles of HCl added 0.48 M * 0.79 mL 0.3792 mmol When HCl adds to the buffer solution, it reacts with HPO42 to f

(b) Number of moles of NaOH added M*V = 0.48 M * 0.79 mL 0.3792 mmol When NaOH adds to the buffer solution, it reacts with H2

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