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M Review | Consta Calculate the pH of each of the following strong acid solutions. Part A You may want to reference (Pages 67Part B 0.260 g of HC103 in 1.90 L of solution. Express the pH of the solution to three decimal places. V ALQ * R 0 2 ? pH = S

Part C 5.00 mL of 1.30 M HCl diluted to 0.600 L. Express the pH of the solution to three decimal places. V AED o 2 ? pH = Sub

Part D A mixture formed by adding 44.0 mL of 2.5x10-2 M HCl to 160 mL of 1.5x10-2 M HI. Express the pH of the solution to two

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a): PH = -log [H + 2.22 Nog -> H+ + NO2 - MHNO3 givers [H+]= 2.22x10-2 above and cone of Ho A see above Epu ☺ - Thue Thuc pHun fiml Balistiem fisist poleeste lauty of lucitor forro movi : M.V 1.3 x 5 x 103 = M2_* 0.600 5ml e E - → Mo. 0.01083 = [H+

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