Question

4. Consider the reaction of aluminum and oxygen:
         Al(s) + O2(g)  Al2O3(s)
    (i). Which is the limiting reactant if we start with 30.0 g Al and 30.0 g O2?
    (ii). What is the Theoretical Yield for the reaction?
    (iii). If 25.85 g of Al2O3 was collected at the completion of the
             reaction (actual yield), what is the % yield for the reaction?
5. (a). A 1.506-g sample of limestone-containing material gave 0.558 g of CO2, in addition to CaO, after being heated at a high temperature. What was the mass percent of limestone (CaCO3) in the original sample?
             CaCO3(s) → CaO(s)    +   CO2(g)
5 (b). How many grams of calcium carbonate can be consumed by 45.5 mL of 0.125 M H2SO4 (aq)?


6. What volume of 0.600 M HC2H3O2, acetic acid, is required to neutralize 25.0 mL of 0.175 M    Ca(OH)2?
     2 HC2H3O2 + Ca(OH)2  Ca(C2H3O2)2 + 2H2O
   What mass of pure acetic acid is required?

Answer 1

Sol upion 4AI)30,la) 2ALO3 LBalonced eqn) imdes of aluminim 3moles of O wth ith 16g of Onxgen eact AI eact AI react ith 104 13 of 92 9 of Oxgen AI A1 eact ox 92 47-69 Oxgen ith Hence mafning Only oxYen sleft Aluminiom used 2 he 2initin reagent becau fully consuntat i Theoitical ield moles of broduct tormed K molecular weizt of edsct of product faxmed Moles 1 IS3 Moles 26 2 moles at Al, 03 Hmoles of Al give 1 253 mole gve S763ales 1-253 2 thon 58.269 76 x101 17 TPerd Theoritical Actualrield Haeoriical yie ld Ly.36% as.85 xlop 58.269

Cacosa) Cao(s) t Co,Li) Imol CacO give Lot co requic mole Means loo of Caco Ca coz 2.272 of 44 SS3 ofcor require SS8 2. 272 1-263gof Cacos Total Maperal Mars %o af Caco3 Mars af Cacos bresent Mars af Matesfao 208 x1o lao 4.2- 1 SoC Ca SO4 tCo, t H, C Caco3 t HsOu aeact wite mole of Caco3 Lmole itre Molanty x olume -3 125 US SK10 HSOu Moles of 3 S.687 x10 1 3 m01 es ২০ -3 MOles 1o0 S. 687 K lo Ca co 3 Mars of

CaloH t2CH COOH caleH, CoO) 2 mole ap Ch CoOH Molasiy 175 x 25 xlo 4.37SX/O Moles IMole Then Calon) react with moles cabH) 3 1 Tuen moles 0eles of CaloH 2 x 4.37SKIO -3moles CH3 COOH is 3 8.75 X10 Molarity Then Mole Volumein L) 600 1 Volume 8 7Sxlo3 volume 600 - 3 14.58 x l0 Nolume 14.52 mL Molesx M oleculay acetic acid Mass - 3 D-75x10-X 60 525&