Question

5. Suppose a brand of lacquer thinner is comprised of the following organic compounds by mass 65.0% methylbenzene (toluene), 25.0% 2-butanone, 10.0% 2-methyl-1-propanol. a. What is the concentration of each component of that solution in mole fraction? b. If the vapor pressures of each of those components of the lacquer thinner at 20.0 °C are as follows: Proluene 22.0 torr, P2-buanone = 71.0 torr, and P2methyl-1-propanol 8.0 torT Calculate the vapor pressure of each component of that lacquer thinner in a closed container at 20.0 °C c. What is the total vapor pressure of the mixture. (Hint: Just add them up. We'll discuss this concept in more detail during the gas unit.) d. What is the most abundant component in the vapor? (Hint: Look for the biggest number.) d. Explain why 2-methyl -1-propanol has the lowest vapor pressure of those 3 components.

Answer 1

Nov-2 % by mass = mass of component xoo mass of solution her solution is thinner (het 100 g af sample) орсим и 1. Пионе (т) = 6s (653) 2.2-butanone (8) = 257 (259) 1. 3. 2-methyl-1-propond (P) = 10% (10g) Мел имам 4 т = (с. Н; сня) - 92 g/mus B = (CH3COCH2 CH3) = 72g/mol P = (CH3 CH(CH3) CH, OH) = 749 /uwt o al moles = mass моя wal mole fraction of component = no al moles of component 0 (20) - Total no. of mole of all components 1 659 -= 0.35 72g/mol n = 24 n3 = 92371 92 g/uit = 1.4) (n +no+nB = ne 259 0.34 749 /me 0.71 ni 0.7140.34 +0.35 natnptnB - XP = Пg -10-24 nt tnp+hB xo = nB = 10.25! nytne +MB From Dalton's law of partial pressure Ръ ( Тcal priмши") = <r r, tx, r, t Yв Р? . where pe , pop, på are vapor pressure of three solvents Pt = X Porn = 0.51 X22 tory = 11:22_ton 1. Pp = xp pop = 0.24X71 toss = 117.04 torr most PB = 2B PO = 0.25X8 tony = 2_toss? - P(total) = Pt + Pp + pq = (30.26 tore/ 2- Huf - 3-рлораллоl hоu м салхче крие , aud uѕио ike blace in H-bonding due to which intermolecular force E attrachon is highheet and hence least vaporized."