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The temperature of an object increases by 48.3 °C when it absorbs 3701 J of heat. Calculate the heat capacity of the object.

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Answer #1

1)

Given:

Q = 3701 J

ΔT = 48.3 oC

use:

Q = C*ΔT

3701 = C*48.3

C = 76.6 J/oC

Answer: 76.6 J/oC

2)

Specific heat capacity,

Cs = C/mass

= 76.6 J/oC / 319 g

= 0.240 J/g.oC

This is silver

Answer: silver

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