Question

How many totalmoles of atomes 0 4.86 moles N₂ O₂ 04.01 moles HNO3 ③ 0.337 mole C₂H60 @ 5.50 moles (NHU)2S

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Answer 1

0 4.86 male of N₂02 I mole 20₂ have male of atom (2mal N & 2 mal o atoms) then 4.86 mole of N₂O₂ = 4 x 4.86 mol = 19.44 mol of atoms. ③ 4.01 mole HNO3 I mole HNO₃ = 5 mol of atom [1 +IN+30=5alom] 4.01 mole HNO = 4.01 5 mal = 20.05 mol of atoms then ③ 0.337 make C2H2O I mole ₂H₂O = 9 mol of atoms [26+6H+10=gatom) then 0.337 mol C₂H₂O = 9x 0.337 mol = 3.033 mol of atoms 5. So male of (Allulas Imole (NH4)₂S = 11 mol of atom (2N+8H+ Is= 11 akan then s. somol (NH4), S = S.Sox 11 mal = 60.5 mol of atoms