What is the formal charge on the oxygen to the left in the molecule below?
The formula of formal charge is:
Formal charge = [# of valence electrons] – [electrons in lone pairs + 1/2 the number of bonding electrons]
For O:
# of valence electrons for O = 6
It has one bond.
So, number of bonding electrons = 2
It has 3 lone paints.
So, electrons in lone pairs = 6
Formal charge =6 - (6 + 1/2 * 2)
= 6 - 7
= -1
Answer: -1
What is the formal charge on the oxygen to the left in the molecule below?
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