Question

7.00 g of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass o

0 0
Add a comment Improve this question Transcribed image text
Answer #1

let in compound number of moles of C, H and O be x, y and z respectively

Number of moles of CO2 = mass of CO2 / molar mass CO2

= 23.7/44

= 0.5386

Number of moles of H2O = mass of H2O / molar mass H2O

= 4.85/18

= 0.2694

Since 1 mol of CO2 has 1 mol of C

Number of moles of C in CO2= 0.5386

so, x = 0.5386

Since 1 mol of H2O has 2 mol of H

Number of moles of H = 2*0.2694 = 0.5389

Molar mass of O = 16 g/mol

mass O = total mass - mass of C and H

= 7.0 - 0.5386*12 - 0.5389*1

= -2.525*10^-3

Since this is negative, there is no oxygen present.

Divide by smallest to get simplest whole number ratio:

C: 0.5386/0.5386 = 1

H: 0.5389/0.5386 = 1

So empirical formula is:CH

Molar mass of CH,

MM = 1*MM(C) + 1*MM(H)

= 1*12.01 + 1*1.008

= 13.018 g/mol

Now we have:

Molar mass = 26.0 g/mol

Empirical formula mass = 13.018 g/mol

Multiplying factor = molar mass / empirical formula mass

= 26.0/13.018

= 2

So molecular formula is:C2H2

Answer: C2H2

Add a comment
Know the answer?
Add Answer to:
7.00 g of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • 7.00 g of a certain Compound X, known to be made of carbon, hydrogen and perhaps...

    7.00 g of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of 70. g/mol, is burned completely in excess oxygen, and the mass of the products carefully measured: mass product carbon dioxide 22.01 g water 9.01 g Use this information to find the molecular formula of X, x 6 ?

  • 6.50 g of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar...

    6.50 g of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of 78. g/mol, is burned completely in excess oxygen, and the mass of the products carefully measured: product carbon dioxide mass 22.01 g water 4.50 g Use this information to find the molecular formula of X, x 6 ?

  • 6.00 g of a certain Compound X, known to be made of carbon, hydrogen and perhaps...

    6.00 g of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of 26. g/mol, is burned completely in excess oxygen, and the mass of the products carefully measured: product mass carbon dioxide 20.31 g water 4.16 8 Use this information to find the molecular formula of X.

  • 3.50 g of a certain Compound X, known to be made of carbon, hydrogen and perhaps...

    3.50 g of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of 160. g/mol, is burned completely in excess oxygen, and the mass of the products carefully measured: product mass 5.78 g carbon dioxide 1.58 g water Use this information to find the molecular formula of X.

  • 8.50 g of a certain Compound X, known to be made of carbon, hydrogen and perhaps...

    8.50 g of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of 70. g/mol, is burned completely in excess oxygen, and the mass of the products carefully measured: 굶 product mass carbon dioxide 26.72g water 10,94 alo Use this information to find the molecular formula of X

  • 2.00 g of a certain Compound X, known to be made of carbon, hydrogen and perhaps...

    2.00 g of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of 136. g/mol, is burned completely in excess oxygen, and the mass of the products carefully measured: product mass 5.18 g carbon dioxide 1.06 g water Use this information to find the molecular formula of X. ? X

  • 1.50 g of a certain Compound X, known to be made of carbon, hydrogen and perhaps...

    1.50 g of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of 138. g/mol, is burned completely in excess oxygen, and the mass of the products carefully measured: product carbon dioxide water mass 3.35 g 0.59 g Use this information to find the molecular formula of X. x 6 ?

  • 2.50 g of a certain Compound X, known to be made of carbon, hydrogen and perhaps...

    2.50 g of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of 78. g/mol, is burned completely in excess oxygen, and the mass of the products carefully measured: mass product carbon dioxide 8.46 g 1.73 g water Use this information to find the molecular formula of X X 5 ?

  • 6.00 g of a certain Compound X, known to be made of carbon, hydrogen and perhaps...

    6.00 g of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of 176. g/mol, is burned completely in excess oxygen, and the mass of the products carefully measured: product carbon dioxide mass 9.00 g water 2.46 g Use this information to find the molecular formula of X. x 6 ?

  • 6.00 g of a certain Compound X, known to be made of carbon, hydrogen and perhaps...

    6.00 g of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of 78. g/mol, is burned completely in excess oxygen, and the mass of the products carefully measured: product carbon dioxide mass 20.31 g 4.16 g water Use this information to find the molecular formula of X. X 5 ?

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT