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A spring with a mass on the end of it hangs in equilibrium a distance of 0.4200m above the floor. The mas is pulled dow...

A spring with a mass on the end of it hangs in equilibrium a distance of 0.4200m above the floor. The mas is pulled down a distance of 0.0600m below the original position, released, and allowed to oscillate. How high above the floor is the mass at the highest point in its oscillation? Show work.
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Answer #1
x = 0.060 m from the original position
mass at the highest point in its oscillation is 0.06+0.42 = 0.48 m from the ground
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Answer #2

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Maximum displacemnt above the equilibrium will be same as the maximum displacement below the equilibrium.

distance above the quilibrium A = 0.06 m

height above the floor = height of equilibrium above the floor + A

= 0.420 + 0.060

= 0.480 m

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Answer #3

Tawing hi

above persons answer is correct if spring oscillates horizontally or potential energy due to gravity is not considered :D

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