Question

6) Which of the following is a possible set of quantum numbers for a 4f electron? (n, t, me, m) A) 4,2, 1,- B) 3,4, 3,+ C) 4,3, 3,+ D) 4, 2, 2,+½ E) 4, 3,-4,-½ 7) 7) Choose the ground state electron configuration for Cr. A) [Ar]4s 3d B) [Ar]4s 3d C) [Ar]4s 3d D) [Ar] E) [Ar]3d 8) 8) Calculate the wavelength, in nanometers, of an x-ray that has frequency of 5.15 x 10 s A) 1.72x 10 B) 583 C) 5.83 D) 0.172 E) 17.2 Table 8.1 Consider the partial Periodic Table reproduced below. Ge Sn 9) Refer to table 8.1. Which element has the greatest (most negative) electron affinity? 9) A) Sn B) Se C) Ge D) Te 10) Which of the following sets is NOT an acceptable set of quantum numbers. 10) A) n-3, {= 1, mg-3 B) n-7,-3, m+3 C) n-2,t-1, m +1 D) n 1,-0, m0 E) n-2,(-1, m-1

Answer 1

6 for a 4f electron principal quantion number (Talks about. energy & size n=4 for n, the value of ļ varies from o to n- of shell) .l= 0,1,2,35 Azimuthal Duantem Numse " srd (Shape of orbitalo) fore, the value of me varies from I tol ie when I co, meco dal, me = -1,0,1. (magnetic quantum Number) orientations of orbitals) l= 2, me =-2,-1,0,1,2 spin quantum Number) 1-3, m,--3,-2,-1,0,1,2,3 in spain of e-in clockwire for Auti-clockivise direction. to, Answer is (C) 4,3,3,+/ in, l, m, sy ms ) (79.9CV:422822p+24*3 pc 484 oder In Crt3 By Cr ; [Arhus Cr : [Ar] YA'3ds (first election will be removed le from 3ds subshell) from us and then so ver : [Ar]3d² (Annever is e)

cart wavelength of an X-ray 8. De 5:15 Xlol H2/07 Cout frequency of X-ray - speed of lights in air so, optian (C) correct. 00583 no į = 3x/08 ORBS X10-8 m 16 5.15X 583 do seres x 10-9m (Inm = lo d 2 s@1823 mm nanometre 75.83 nm

9816 9. Ge en Te G816 elements have higher ore value of electron affinity than GP 14 elements and as we move down the group are value of Electron affinity decreases. so, se has the greatest (most negative) electron option (B) affinity ů correct 10. for n, the value of l varies from o to no for I the value of me varies from I to I including zero, So, when (A) is answer 1. When na3, e=1 , me = -3 (8) as me can have values -1,0,1 so-3 Can't be value of me corresponding to l=1 so that's why part its is the auswer.