Solution:-
2) Probability that both are 40 or older = 0.68 x 0.68 = = 0.4624
3) P(X = 5) = 0.73^5 = 0.2073
4) a) P(Both Spades) = (13/52)(12/51) = 156/2652 = 1/17
b) P(Both same suit) = 12/51
c) P(both are kings) = 8C2/52C2 = (8*7)/(52*51) = 0.0211
5) P(select 2 defective) = 2C2/6C2 = 1/15
6) P(5 buy at least one) = 1 - P(none of 5 buy at least one) = 1 - 30C5/120C5 = 0.999252
7) a) P(all are jacks) = 4/52 * 3/51 * 2/50 = 1/5525
b) P(all are clubs) = 13/52 * 12/51 * 11/50 = 11/850
c) P(all are red card ) = 26/52 * 25/51 * 24/50 = 2/17
h) Eating an extu cigarettes 2, A survey found that 68% of book buyers are 40 or older. If two book buyers are selecte...
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