HomeworkLib
Question

A 100.00 mL volume of 0.500 M HCl was mixed with 100.00 mL of 0.500 M KOH in a constant pressure calorimeter. The initial tem

science   chemistry   
0 0
Add a comment Improve this question Transcribed image text
Next > < Previous
Sort answers by oldest

Homework Answers

Answer #1

Heat loss = heat gain

Acid-Base Reaction is neutralisation and This i Reaction is exothermic and energy Releases tralisation enthalpy of Stronggm eruivalent a NV(me) = NV (b) = We z nx moles 1000 HU n=1 = No. of Ho don releases Ma=0.500M , Va = 200ml Ny = 1X0.500 = 0-Va = 100+100 = 200 ml d=1.02 g/ml s= 3.97 Ilgm d= m . massz do va = Ti = 22.50 °C 1.02 X 200 = 204 gm T = 25.80°C solution =

0 0
Add a comment
Know the answer?
Add Answer to:
A 100.00 mL volume of 0.500 M HCl was mixed with 100.00 mL of 0.500 M KOH in a constant pressure calorimeter. The initi...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions

  • When a chemist mixed 3.33 g of LiOH and 255 mL of 0.62 M HCl in...

    When a chemist mixed 3.33 g of LiOH and 255 mL of 0.62 M HCl in a constant-pressure calorimeter, the final temperature of the mixture was 23.4°C. Both the HCl and LiOH had the same initial temperature, 20.4°C. The equation for this neutralization reaction is: LiOH(s) + HCl(aq) → LiCl(aq) + H2O(l). Given that the density of each solution is 1.00 g/mL and the specific heat of the final solution is 4.1801 J/g·K, calculate the enthalpy change for this reaction...

  • 100 mL of 0.500 M HCl is mixed with 100 mL of 0.600 M NaOH in...

    100 mL of 0.500 M HCl is mixed with 100 mL of 0.600 M NaOH in a constant pressure calorimeter. The initial temperature of the solutions is 22.50 C and the final temperature of the mixed solution is 25.86 C. Calculate ?rH (in units of JK/mol-rxn) for the reaction NaOH(aq) + HCl(aq) -> NaCl(aq) + H2O(l) The density of the resulting solution is 100 g/mL, and its specific heat is 4.184 J/(g C). Thank you in advance!

  • A 48.53 mL volume of 1.00 M HCl was mixed with 47.70 mL of 2.00 M...

    A 48.53 mL volume of 1.00 M HCl was mixed with 47.70 mL of 2.00 M NaOH in a coffee cup calorimeter (with calorimeter constant = 26.0 J/°C) at 21.43 °C. The final temperature of the aqueous solution after the reaction was 29.71 °C. Assuming that them heat capacity of the solution is 4.18 J/g/°C, calculate the following: a. The total mass of aqueous solution inside the calorimeter (dsoln = 1.00 g/mL) g b. The change in temperature (∆T) of...

  • When 27.0 mL of 0.500 M H2SO4 is added to 27.0 mL of 1.00 M KOH in a coffee-cup calorimeter at 23.50°C, the temperature...

    When 27.0 mL of 0.500 M H2SO4 is added to 27.0 mL of 1.00 M KOH in a coffee-cup calorimeter at 23.50°C, the temperature rises to 30.17°C. Calculate ΔH of this reaction. (Assume that the total volume is the sum of the individual volumes and that the density and specific heat capacity of the solution are the same as for pure water.) (d for water = 1.00 g/mL; c for water = 4.184 J/g·°C.) Answer: ______  kJ/mol H2O

  • 2. A 49.45 mL volume of 1.00 M HCl was mixed with 49.14 mL of 2.00...

    2. A 49.45 mL volume of 1.00 M HCl was mixed with 49.14 mL of 2.00 M NaOH in a coffee cup calorimeter (with calorimeter constant = 25.1 J/°C) at 21.34 °C. The final temperature of the aqueous solution after the reaction was 29.37 °C. Assuming that them heat capacity of the solution is 4.18 J/g/°C, calculate the following: e. The enthalpy change (∆H) for the neutralization in kJ/mol HCl ( this should be a negative number) e. The enthalpy...

  • A 48.71 mL volume of 1.00 M HCl was mixed with 47.19 mL of 2.00 M...

    A 48.71 mL volume of 1.00 M HCl was mixed with 47.19 mL of 2.00 M NaOH in a coffee cup calorimeter (with calorimeter constant = 26.1 J/°C) at 20.69 °C. The final temperature of the aqueous solution after the reaction was 27.02 °C. Assuming that them heat capacity of the solution is 4.18 J/g/°C, calculate the following: The total mass of aqueous solution inside the calorimeter (dsoln = 1.00 g/mL) =______g The change in temperature (∆T) of the aqueous...

  • When 27.4 mL of 0.500 M H2SO4 is added to 27.4 mL of 1.00 M KOH...

    When 27.4 mL of 0.500 M H2SO4 is added to 27.4 mL of 1.00 M KOH in a coffee-cup calorimeter at 23.50°C, the temperature rises to 30.17°C. Calculate ΔH of this reaction. (Assume that the total volume is the sum of the individual volumes and that the density and specific heat capacity of the solution are the same as for pure water.) (d for water = 1.00 g/mL; c for water = 4.184 J/g·°C.) kJ/mol H2O

  • In a coffee cup calorimeter, 50.0 mL of 1.00 M NaOH and 50.0 mL of 1.00...

    In a coffee cup calorimeter, 50.0 mL of 1.00 M NaOH and 50.0 mL of 1.00 M HCl are mixed. Both solutions were originally at 24.6°C. After the reaction, the final temperature is 31.3°C. Given that the density of the NaCl solution is 1.038 g/mL and he specific of NaCl solution is 3.87 J/g-°C, calculate the ΔHneut/mole for the reaction of HCl with NaOH. Assume that no heat is lost to the surroundings. Part A. ) Why are the density...

  • 2. A 49.21 mL volume of 1.00 M HCl was mixed with 48.05 mL of 2.00...

    2. A 49.21 mL volume of 1.00 M HCl was mixed with 48.05 mL of 2.00 M NaOH in a coffee cup calorimeter (with calorimeter constant = 25.6 J/°C) at 20.32 °C. The final temperature of the aqueous solution after the reaction was 29.83 °C. Assuming that them heat capacity of the solution is 4.18 J/g/°C, calculate the following: a. The total mass of aqueous solution inside the calorimeter (dsoln = 1.00 g/mL) g correct 1/1 b. The change in...

  • 100 mL of 0.1 M HCl are mixed with 100 mL of 0.25 M NaOH. If...

    100 mL of 0.1 M HCl are mixed with 100 mL of 0.25 M NaOH. If the temperature of solution rose 5.0 degree C, what is the heat of reaction? Heat lost by_____ = - Heat gained by _____

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT