Calculate the energy of a photon of radiation whose wavelength is 421 nm

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Question

science chemistry

Answer 1

Answer #1

wavelength = 421 nm

Energy = h C / lamda

= 6.626 x 10^-34 x 3 x 10^8 / 421 x 10^-9

= 4.72 x 10^-19 J

energy of a photon = 4.72 x 10^-19 J

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Answer 2

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