Determine the volume (in L) of a 0.0764 M solution of K3PO4 that contains 38.7 g of K3PO4.
Molarity = number of moles of K3PO4 / volume of solution in L
number of moles of K3PO4 = 38.7 g / 212.27 g/mol = 0.182 mole
0.0764 = 0.182 / volume of solution in L
volume of solution in L = 0.182 / 0.0764 = 2.38 L
Therefore, the volume of solution = 2.38 L
Determine the volume (in L) of a 0.0764 M solution of K3PO4 that contains 38.7 g of K3PO4.
Determine the volume (in L) of a 0.0344 M solution of K3PO4 that contains 24.7 g of K3PO4. Answer: _____ L
Determine the volume (in L) of a 0.0584 M solution of K3PO4 that contains 32.7 g of K3PO4.
Determine the volume (in L) of a 0.0584 M solution of K3PO4 that contains 32.7 g of K3PO4.
Determine the volume of solution that contains 15.0 g of AgNO3 if the solution is 0.375 M 235 mL 31.5 mL 247 ml 33.1 mL
A solution is 0.540 M NaOH. What volume contains 15.5 g of NaOH? a) 0.202 L b) 0.718 L c) 1.15 L d) 1.40L
A 3.313 M solution contains 205 g of H2SO4. What is the volume of the solution? Provide your answer below: L
2. What is the molarity of a solution in which 38.7 g of NaCl is dissolved in enough water to make a total of 1.00 L of solution? answer 3. What is the molarity of a solution in which 10.0 g of AgNO3 is dissolved in 500. mL of solution? answer 4. How many grams of K2SO4 would it take to make 1.50 L of a 0.500 M solution? answer 5. Calculate the % (m/V) of a 0.0600 L solution...
1) What is the volume of a 1.20 M HNO3 (aq) solution that contains 0.0420 moles of HNO3 ? 2) What is the volume (in mL) of a 0.125 M Ba(ClO4)2 solution that is needed, to completely react with 20.00 mL of 0.250 M K3PO4 solution according to the reaction below ? 3 Ba(ClO4)2(aq) + 2 K3PO4(aq) → Ba3(PO4)2(s) + 6 KClO4(aq)
What volume of 0.205 mol/L K3PO4 solution is necessary to completely react with 154 mL of 0.0114 mol/L NiCl2? Express your answer in Liters
A 0.70 M solution contains 3.0 g of potassium chlorate (KClO3). What is the volume of the solution? 0.023 L or 0.038 L or 0.045 or 0.035 L