Question

please help!

how to find the miss values knowing 3-methylcyclohexanol react with phosphoric acid and sulfuric acid?

Compound mmol Equiv. Rxn quant. (units?) MF MM (g/mol) 114,19 (g/ mL) 3-methylcylcohexanol phosphoric acid, conc. (14.8 M) sulfuric acid, conc. H₂PO H2504 10.914 98.00 1.88 98.0011.84 (18.0 M) Oc:

Answer 1

You have to have the amount of the starting compound, relative to which you can figure out the amounts of the acids for dehydration. Although only catalytic amount of the acid is required, you can use the calculated amounts.

Lets take 1 equiv. of the substrate $\equiv$ 10 mmol of the substrate $\equiv$ (10 x 114.19)/0.914 mL i.e. 1.25 mL of substrate.

Then 1 equiv. of each of the acids can be used in both reactions.

Conc. H₃PO₄ : 1 equiv. $\equiv$ (10/3) mmol [as it is tribasic acid] $\equiv$ (10/3)*(1000/14800) mL = 0.225 mL .

Conc. H2SO4 : 1 equiv. $\equiv$ 5 mmol [dibasic acid] $\equiv$ (5*1000)/18000 mL = 0.28 mL .

OH C H₂SO4 + a + H20 me - me n a I eq. c. 4₂P04 (Catalytic amount) lea- calculated taking the of the starting compound. nd n is reacting, & take NI n. quart. (me) m.mol eqir the quantities can be relative to the quantity let's say, 10 mmol of that as 1 equivalent ho 1:25 Сме I Co H₃PO4 0-225 (14.8 M) Tc. H₂SO4 08.0M 10 1/3 0.28 5