
Question 2 1 pts Identify the group number of the element that has the following successive ionization energies (in...
Question 5 1 pts Identify the group number of the element that has the following successive ionization energies (in kJ/mol). IE1-577 IEs 14,800 IE6 18,400 IE 23,300 E2-1,816 IE3 2,881 IE4 -11,600 O Group 2A O Group 7A O Group 3A O Group 5A Previous Next
Identify the group number of the element that has the following successive ionization energies (in kJ/mol). IE1 = 1,060 IE5 = 6,270 1E4 = 4,950 IE2 = 1,890 IE6 = 21,200 E3 = 2,905 IE7 = 25,400 Group 5A O Group 7A Group 4A Group 3A O Group 6A
Question 2 1 pts Identify the group number of the element that has the following successive ionization energies (in kJ/mol). IE1 = 590 IE5 = 8,153 IE2 = 1,145 IE6 = 10,490 IE3 = 4,912 IE4 = 6,490 E7 = 12,270 Group 5A Group 2A O Group 4A O Group 3A Group 6A
Identify the group number of the element that has the following successive ionization energies (in kJ/mol). E1 = 1,060 IE2 = 1,890 IE3 = 2,905 IE4 = 4,950 IE5 = 6,270 IE6 = 21,200 IE7 = 25,400
4. Consider an element of Period 2 which has the following successive ionization energies, in kJ/mol. What is the charge of the common ion? IE1, 1314 IE2, 3389 IE3, 5298 IE4, 7471 IEs, 10992 IE6, 13329 IE7, 71345 IE8, 84087 (1) -1 (2) –2 (3) –3 (4) +6 (5) +7
Question 23 2 pts What element in period 3 has the following successive ionization energies? 1E1:578 kJ/mol IE2: 1817 kJ/mol 1E3: 2745 kJ/mol IE4: 11578 kJ/mol IES: 14842 kJ/mol IE6: 18379 kJ/mol 1E7:23326 kJ/mol IE8:27464 kJ/mol
a new element X is discovered that has the following successive ionization energies (kj/mol) IE1=1004 , IE2=1251 IE3=5988 , IE4=6220 , IE5=6803 , IE6=7178 a. what group (column) do you expect this element will belong? explain b. if this element X combined with fluorine , what is the likely molecular formula?( for example XF2, X2F3, etc)
10.) Below is a list of successive ionization energies (in kJ/mol) for a period 3 element. Identify the element and explain how you came to that conclusion. IE2 = 2250 IE3 - 3360 TE 4 = 4560 IE5 = 7010 IE6 - 8500 IE 7 = 27,100
15. Below is a list of successive ionization energies (in kJ/mol) for a period 3 element, X. What is the most likely formula for a stable ion of X? 151 = 1000 IE2 = 2250 IE3 = 3360 IE4= 4560 E5= 7010 TE6= 8500 IE2 = 27.100 d. X a. X2 b. X30 c. X²
Identify the element of Period 2 (name) which has the following successive ionization energies, in kJ/mol. IE1 = 1314 IE2 = 3388 1E3 = 5301 JE4 = 7469 IE5 = 10989 IE6 = 13327 1E7 = 71330 IE8 = 84078 Answer: