Question

>>> QUESTION: Calculate the mass and volume of 150 mmol of benzaldehyde, and the theoretical yields of benzoin, benzyl, and benzilic acid expected from that much benzaldehyde. You will find mol molecular weight below!

Reactions and molar ratios:

A. Benzoin condensation OOH 20 CHO thiamine NaOH Tc-culo - --CH- -CHO benzaldehyde benzoin

Phyiscal properties:

Answer 1

solution: Q. We have 150 mmol of benzaldehyde = 150 x 103 mol molar mass of benzaldehyde = 106. 1 gl moto mass of benzaldehyde = 150x10 mos x 106.1g/mol = 15915 g/ density of benzaldehyde = 1.042 g/mL o density = mass me volume = mass / density 315.915% -15,27 me volume 115. 27 me 1.042gim Theoretical yields Ai Benzoin condensation - According to above reaction:- - 1 mol of benzaldehyde gives Imol of benzoin ! so, 150 mmol of benzaldehyde gives - 150 mmol of benzoila, = 75 mmol of benzoin. Theoretical yield of benzoin : (100ommol = 1mal) ho, of moles of benzoion & molar weight of benzoin. = 0.075 mol x 212-2 g/mol = 115.915 g of benzoin

Bi Oxidation of benzoin According to above reaction I mol of benzoin gives I mol of benzin so, 75 mmol of benzoin gives 75 mmol of benzil. = 0.075...mol of benzil Theoretical yield of benzil: no. of moles of benzil x molar weight of benzil = 0.075 mol X 210.2 g lmol. = = 15.765 g of benzilt L! Bestzittinetad rearrangement: . 2 According to given reaction timol of benzil gives Imol of benzillic acid. -. So, 0, 075 mol of benzil gives 11x0,075 mol of benzillic acid = 0.075 mol of benzillic acid 3 Theoretical yield of benzillic acid: no, of moles of benzillic acid x mol, weight of - benzillic acid 0.075 mol x 228.2 91 mot = 17,115 g of benzillic acid