Question

For the following situation, find the mean and standard deviation of the population. List all samples (with replacement) of the given size from that population and find the mean of each. Find the mean and standard deviation of the sampling distribution and compare them with the mean and standard deviation of the population The scores of three students in a study group on a test are 90.94, 96. Use a sample size of 3.D The mean of the population is (Round to two decimal places as needed.) The standard deviation of the population is (Round to two decimal places as needed.) Identify all samples of size 3 with the correct accompanying means below A 94,90,90 x = 91.33 B. 96,96,90 X =94 D. 94 96.90 x = 93.33 E. 90.96,90 X = 92 G. 96.94.90 X = 93 33 H. 94.90.9429267 J. 90,96,96 x 94 K 90.90.90 X 90 M. 96.94.969533 IN 96.96.94 89533 0.96.90.90 R-92 DP 94.94.96 94 67 S. 96.94,94 = 9467 T 90.96.29333 W. 9496947=9467 IV. 94 94 90 X = 92 67 C. 90,94,94 392.67 OR 94,94,9494 OL 96.96.9696 OL 96.90943933 0.90.90.9692 R. 90.90.943.9133 DU043-9333 DX 90 95 94 ccessClick to select your answers) Libre

Answer 1

Given, sample data, x: go, 94,96 n=3 x = E = 98.39953 = = = 9.5555 nd The mean of the population = M = x = 93.33333 =98.35 population = = The standard deviation of the 1 (mos? (933333) = √6.222222 = 2.494458 = 2.49 . . Samples that are correct accompanying means are, DIGI LITIU