Question

Attempt 5 Question 9 of 24 If a solution containing 72.957 g of mercury(II) chlorate is allowed to react completely with a solution containing 10.872 g of sodium sulfide, how many grams of solid precipitate will form? precipitate: 32.410 How many grams of the reactant in excess will remain after the reaction? excess reactant: 30.174 Publisher Unversity Science Books M-General Chemisty Question Soure careen pricy cy s of u aact help about u etve MacBook Pro Seareh or enter website name & delete 7 5 6 4 P Y K F в option command + C V MM IN I T

Answer 1

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Dear Studerrt The reaetiem invoued iu Ha (Cag) +NasS Ca)Hto+ aNatia laa) z +9.957 moles mar ot +2.95+8 36-4981mal 0.19 85 moles 10.812 Nas wt malu mal.ot (0-3+29 8.O152gmel mal O-1393 moles to the heactien, Imala. ala heaonaing O.1985 Peact nith Imol ot No SThu will leact oith 0.1985 moles Nas but he have o-1393 mele NoC Nos the limhngeg PTO mde Thus

1mmal 01393 melu Na il am Thus =0.1393 malaHas O-1393 mol x da mol st 32.41 A& per thi xuaction, O.1393 moles Nowll east ith 1gr Oa1393 molu Coift afte Aeaeten O 1985-0.1393 Thuu mole . 059 male HigCedea z 00592 moles X 3t.49 mal But ouhu