Question

Please show all your work.

5) Acceleration is to velocity as velocity is to position . aaux"# r where vr įs the instantaneous velocity. So the average acceleration is about how rapidly the instantaneous velocity is changing, and the sign tells about the direction of the change. At For the pendulum, you made estimates of the instantaneous velocity for ←2.05[s] and t= 2.5%]. Also, the average speed and average velocity estimates that you made at other times may be reasonable estimate of the instantaneous values (depending on how much the motion was changing during the time interval). The velocity vs time graph below is made by doing a similar thing for all the times in the pendulum vidco. 8.00 6.00 4.00 2.00 0.00 2.00 4.00 6.00 8.00 0.00 0.50 1.00 1.50 2.00 2.50 3.00 3.50 Time [s 5.1) How do your estimates of the instantaneous velocity at t-2.05[s] and t-2.50[s] from part 3 compare to what the graph says? 5.2) Find the average acceleration for the pendulum for the time intervals in the table. Use the graph to find the instantaneous velocities at the start and end of each time interval. Distance Average Traveledacceleration Time of Starting Ending interest [s Time [s) Starting v End m s 0.70 | 0.50 0.90 1.10 0.90 1.30 2.30 2.05 2.50 9 330 3.10 2.90 The instantaneous acceleration (which we just call acceleration) is just the average acceleration for a short enough" trip. 5.3) So like you did with the other graph, draw the tangent line that touches the curve on only one spot on the velocity graph of the pendulum where t-3.10[s]. Extend it long enough to get fairly large rise and run measurements. Use the rise and run of your line to calculate the acceleration of the car when t-3.10[s]. rise = 5.4a) Imagine that some other object is traveling in the +x direction and is speeding up. When t-0 the speed is 40.0[m/s] and when t-2.00[s] the speed is 50.0fm/s]. Find the following: When t = 2.00[s], aavx u,- When t-o, v,- b) Imagine that an object is traveling in the +x direction and is slowing down. When t-0 the speed is 50.0[m/s] and when t-2.00[s] the speed is 40.0[m/s]. Find the following: av x when t = 2.00[s], th = When t, c) Imagine that an object is traveling in the -x direction and is speeding up. When t-0 the speed is 40.0[m/s] and when t-2.00[s] the speed is 50.0[m/s]. Find the following: aavx when t-2.00[s], u ,- when t= 0, v,-- d) Imagine that an object is traveling in the -x direction and is slowing down. When t-0 the speed is 50.0[m/s] and when t-2.00[s] the speed is 40.0[m/s]. Find the following: When t-2.00[s], vx avx When t-O, vx e) In general, for an object moving on the x-axis when is ax positive and when is it negative?

Answer 1

Va 5,2 1,5 2 も At 0.3-5.5 15 225 31 2. 3.2

50 ms 1 ms 2 50 Ms 2 -Soms SMS-2 = - ve l