Question

If 2.10 g of CusO, is dissolved in 9.21 x 10- mL of 0.350 M NH2, calculate the concentrations of the following species at equ

The Ksp and Kf values are not given, I think: Kf = 5.0 X 1013

0 0
Add a comment Improve this question Transcribed image text
Answer #1

since mole = mass molar mass moterity x volume (L) notarity X volume molas mass of cusoy = 160g/mol then mole of cusoy, ncusoAnswer :

3.78*10^-14 M

0.293 M

0.014 M

Add a comment
Know the answer?
Add Answer to:
The Ksp and Kf values are not given, I think: Kf = 5.0 X 1013 If 2.10 g of CusO, is dissolved in 9.21 x 10- mL of 0.350...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Be sure to answer all parts. If 2.10 g of CuSO4 is dissolved in 9.05 x 102 mL of 0.380 M NH3, calculate the concentrati...

    Be sure to answer all parts. If 2.10 g of CuSO4 is dissolved in 9.05 x 102 mL of 0.380 M NH3, calculate the concentrations of the following species at equilibrium. Cu2+ 11.8 X L:14 V Enter your answer in scientific notation. NH3 Cu(NH3)42+

  • Be sure to answer all parts. If 2.10 g of CuSO4 is dissolved in 8.75 ×...

    Be sure to answer all parts. If 2.10 g of CuSO4 is dissolved in 8.75 × 102 mL of 0.310 M NH3, calculate the concentrations of the following species at equilibrium. Cu2+ × 10 M Enter your answer in scientific notation. NH3 M Cu(NH3)42+ M

  • If 2.40 g of CuSO4 is dissolved in 8.79 × 102 mL of 0.300 M NH3,...

    If 2.40 g of CuSO4 is dissolved in 8.79 × 102 mL of 0.300 M NH3, calculate the concentrations of the following species at equilibrium. Cu2+ × 10 MEnter your answer in scientific notation. NH3 M Cu(NH3)42+ M

  • Be sure to answer all parts. If 2.25 g of CuSO4 is dissolved in 9.07 ×...

    Be sure to answer all parts. If 2.25 g of CuSO4 is dissolved in 9.07 × 102 mL of 0.320 M NH3, calculate the concentrations of the following species at equilibrium. Cu2+ × 10 MEnter your answer in scientific notation. NH3 M Cu(NH3)42+ M

  • If 2.30 g of CuSO4 is dissolved in 8.65 × 102 mL of 0.330 M NH3,...

    If 2.30 g of CuSO4 is dissolved in 8.65 × 102 mL of 0.330 M NH3, calculate the concentrations of the following species at equilibrium. Cu2+ ___ × 10^__ M Enter your answer in scientific notation. NH3 ___ M Cu(NH3)4^2+ ___ M

  • For CuCO3, Ksp is 2.5 x 10-10 M2. For CuCl42-, Kf is 5.0 x 105 M-4....

    For CuCO3, Ksp is 2.5 x 10-10 M2. For CuCl42-, Kf is 5.0 x 105 M-4. What is the value of the equilibrium constant for the sum of the two reactions shown below? CuCO3 ↔ Cu2+ + CO32- Ksp = 2.5 x 10-10 M2 Cu2+ + 4 Cl- ↔ CuCl42- Kf = 5.0 x 105 M-4 CuCO3 + 4 Cl- ↔ CuCl42- + CO32- K = ? K = ___ M-2 Based on the previous problem, what is the maximum...

  • For CuCO3, Ksp is 2.5 x 10-10 M2. For CuCl42-, Kf is 5.0 x 105 M-4....

    For CuCO3, Ksp is 2.5 x 10-10 M2. For CuCl42-, Kf is 5.0 x 105 M-4. What is the value of the equilibrium constant for the sum of the two reactions shown below? CuCO3 ↔ Cu2+ + CO32-                          Ksp = 2.5 x 10-10 M2 Cu2+ + 4 Cl- ↔ CuCl42-      Kf = 5.0 x 105 M-4 CuCO3 + 4 Cl- ↔ CuCl42- + CO32-                    K = ? K = ___ M-2 Based on the previous problem, what...

  • Please show all work so that it's easy to follow and understand. If 2.35 g of...

    Please show all work so that it's easy to follow and understand. If 2.35 g of Cuso, is dissolved in 0.51 x 102mL of 0.380 M NH3, calculate the concentrations of the following species at equilibrium. x 10M Enter your answer in scientific notation. NH3 Cu(NH3)22+

  • a. Using the Ksp value for Cu(OH)2 (1.6 x 10-19) and the overall formation constant for...

    a. Using the Ksp value for Cu(OH)2 (1.6 x 10-19) and the overall formation constant for Cu(NH3)42+ (1.0 x 1013), calculate the value for the equilibrium constant for the following reaction: Cu(OH)2 (s) + 4NH3 (aq) ⇌ Cu(NH3)42+(aq) + 2OH -(aq) b. Use the value of the equilibrium constant you calculated in part a to calculate the solubility (in mol/L) of Cu(OH)2 in 5.0 M NH3. In 5.0 M NH3 the concentration of OH - is 0.0095 M.

  • 1.Given a solution in which [Cu2+] = 0.20 mol/L and [NH3] = 1.40 mol/L, what is...

    1.Given a solution in which [Cu2+] = 0.20 mol/L and [NH3] = 1.40 mol/L, what is the equilibrium concentration of free Cu2+? The complex Cu(NH3)42+ has Kf = 5.0 X 1013. The answer to the question is 3.1 X 10 -14 I just need how to do it with the work shown. 2. You titrate a 20.00 mL sample of ammonia (Kb = 1.8 X 10-5) to the equivalence point using 10.00 mL of .20 M HCl solution. What is...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT