Homework Answers
7)
At half equivalence point, pH = pKa
So,
pKa = 5.67
use:
pKa = -log Ka
5.67 = -log Ka
Ka = 2.138*10^-6
Answer: 2.14*10^-6
8)
Balanced chemical equation is:
NaOH + HA ---> NaA + H2O
lets calculate the mol of NaOH
volume , V = 30.15 mL
= 3.015*10^-2 L
use:
number of mol,
n = Molarity * Volume
= 9.95*10^-2*3.015*10^-2
= 3*10^-3 mol
According to balanced equation
mol of HA reacted = (1/1)* moles of NaOH
= (1/1)*3*10^-3
= 3*10^-3 mol
This is number of moles of HA
mass(HA)= 0.279 g
use:
number of mol = mass / molar mass
3*10^-3 mol = (0.279 g)/molar mass
molar mass = 93.0 g/mol
Answer: 93.0 g/mol
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