Question

1. A patient received 6 Og of NaCl in 12 hours. How ma were delivered? (3 points) w many milliliters of a 0.90%(m/v) NaCl (saline) solution 8. Calculate the molarity (M) of 350g of NaOH in 240.OmL of solut in 240.0mL of solution. (3 points) 9. What volume in liters is needed of a 3.5M NaOH solution to obtain 1.8moles of NaOH? (3 points) caste the grams of solute, NaNO3, needed to prepare 225ml of a 4.00M NaNO, solution. (3 points)

please show work

Answer 1

7 0.90% (m/v) means there is 0.9 g Nace in 100ml how many mal in Gg - 14 0.99 - a 66 6.7 me - 100ml x 6g Molarity = hast mass of solute - malar mass & Volume of solution = 35g 39.9979/mol x 0.242 3 -65M imeler mass of NaOH = 39.99 Iml = 10-3 L 9 240ml = 240 x 10-3 L: - = 0.24L Malarity & moles of soluto - litres of solution Volume = moleso Molavity 18 mes 3.5 mol/L - 0.514 L grams of salute = Molavity Xmdar mass x Volume of solution - 24MX 84.99479/med X = 76:59 0.225 L