Homework Answers
Balanced chemical equation is:
NaOH + C2H4O2 ---> NaC2H3O2 + H2O
lets calculate the mol of NaOH
volume , V = 14.01 mL
= 1.401*10^-2 L
use:
number of mol,
n = Molarity * Volume
= 0.121*1.401*10^-2
= 1.695*10^-3 mol
According to balanced equation
mol of C2H4O2 reacted = (1/1)* moles of NaOH
= (1/1)*1.695*10^-3
= 1.695*10^-3 mol
This is number of moles of C2H4O2
Molar mass of C2H4O2,
MM = 2*MM(C) + 4*MM(H) + 2*MM(O)
= 2*12.01 + 4*1.008 + 2*16.0
= 60.052 g/mol
use:
mass of C2H4O2,
m = number of mol * molar mass
= 1.695*10^-3 mol * 60.05 g/mol
= 0.1018 g
Use:
Mass % C2H4O2 = mass of C2H4O2 * 100 / mass of vinegar
= 0.1018 * 100 / 2.025
= 5.03 %
Answer: 5.03 %
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i
need all answers
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