
A long hairpin is formed by bending an infinitely long wire, as shown. If a current of 2.8 A is set up in the wire, what is the magnitude of the magnetic field at the point a? Assume R = 11 cm.
let the current flow in an anti-clockwise direction,
magnetic field due to semi-circular wire = 1/2(μI/2r). (in a direction perpendicular to the plane of ur screen)
magnetic field due to upper stright wire(half infinite wire) = 1/2(μI/2πr),(in the same direction)
magnetic field due to lower stright wire(half infinite wire) = 1/2(μI/2πr). (in the same direction)
as three are in same direction add those ans = μI/4r+μI/2πr =
=4π*10-7*2.8[2/(4*π*0.11) + 1/(4*0.11) ]
=4*π*10-7*2.8*2.272
=8.141 x10-6 T
I is the current and 'r' is the radius.
A long hairpin is formed by bending an infinitely long wire, as
shown. If a current of 1.10 A is set up in the wire, what is the
magnitude of the magnetic field at the point a? Assume
R = 4.10 cm.
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I
only need help with questions 4,5,6,7, and 8. thanks
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