Help me for this question by using the properties of regular language, please
Homework Answers
Proof by contradiction -
Let L' = {apbq | p,q are not prime} be a regular language.
Then, by concatenation L' = L1.L2 where L1 = {ap | p
is not prime} and L2 = {bq | q is not prime}
L1 and L2 are regular languages. (concatenation
property)
L1' = {ap | p is prime} therefore L1' is also regular
but this contradicts the given statement that {ap | p is
prime} is not regular. (complement property)
Hence, our assumption that {apbq | p,q are
not prime} is a regular language is also wrong.
Hence, proved.
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SUBJECT:THEORY OF COMPUTATION CAN SOMEONE PLEASE HELP ME I HAVE POSTED IT REPEATEDLY AND I KEEP G...
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