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Question 9 (1 point) Use the following equations to calculate the molar enthalpy of formation for manganese(IV) oxide, MnO2(s
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Answer #1

reverse and double the first equation

2MnO(s) + O2(g) -----------> 2MnO2(s)   \DeltaH1 = -264 kJ / mol

add second equation to above equationj

2MnO(s) + O2(g) -----------> 2MnO2(s)   \DeltaH1 = -264 kJ / mol  

MnO2(s) + Mn(s) ---------> 2MnO(s) \Delta H2 = - 240 KJ/mol

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Mn(s)  +    + O2(g) -----------> MnO2(s) \Delta H = - 504 KJ/mol

answer = option 2 = - 504 KJ/mol

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