A shaft is turning at 67.0 rad/s at time zero. Thereafter, its angular acceleration is given by the following equation, where t is the elapsed time.
α = -10.0 rad/s2 - (4.50 rad/s3)t
(a) Find its angular speed at t = 2.40 s.
rad/s
(b) How far does it turn in these 2.40 seconds?
rad

A shaft is turning at 67.0 rad/s at time zero. Thereafter, its angular acceleration is given by the following equation...
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The angular position of one of the arms of a spinning ice skater for 15 s is described by the function 1000 / (t 5) rad for 0 ts 15 where t is the elapsed time in seconds. rad s2 The angular acceleration at t = 15 s is
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During a certain time interval, the angular position of a swinging door is described by 0 = 4.90 + 9.8t + 2.05t2, where 0 is in radians and t is in seconds. Determine the angular position, angular speed, and angular acceleration of the door at the following times. (a) t = 0 0 = 4.90 rad W = 9.8 rad/s = 4.2 Calculus methods can be used to determine the velocity and acceleration from O(t). rad/s2 α...