density of a noble gas is 2.71g/l at 3.00atm and 0.00C. identify the gas

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science chemistry

Answer 1

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Answer #1

Given, density of noblegas = 2.71 g/L

Pressure P = 3.00 atm

Temperature = T = 0.0 ^oC = 273 K

Theideal gas equation is PV = nRT

= (m /M)RT

P*M = (m/V)RT ( m/V = density of gas)

∴ P*M =d RT ( M = molar mass of gas)

∴ 3.0 atm * M = 2.71 g/L * 0.0821L.atm/mol.K *273K

∴ M = 20.24 g/mol

The noble gas with molar mass 20.24 g/mol is Neon.

Answer 2

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