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presented by Mapo ORGANIC CHEMISTRY ANET L. MAXWELL sapling learning For the following reaction, show the product of one mole of reagent adding across the triple bond, and then show the product of a second mole of reagent. one mole of reagent CI csecond mole of reagent Previous & Give Up & View Solution e Check Answer Next刁Exit- Hint

For the following reaction, show the product of one mole of reagent adding across the triple bond, and show the product of a second mole of reagent.

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Concepts and reason

The concept is to draw the organic products, when an alkyne reacts with one mole of reagent and second mole of reagent.

Fundamentals

Alkynes involve in addition relations. In an addition reaction, one pi bond breaks and two sigma bonds are formed.

Alkyne reacts with one mole of dichlorine (Cl2){\rm{(C}}{{\rm{l}}_{\rm{2}}}) to form 1,2-dichloro substituted alkene is formed.

Alkyne reacts with two moles of dichlorine (Cl2){\rm{(C}}{{\rm{l}}_{\rm{2}}}) to form 1,1,2,2-tetrachloro substituted alkane is formed.

The reaction is,

C12
One mole of reagent
4-methylpent-1-yne
(E)-1,2-dichloro-4-methylpent-1-ene

The reaction is,

Cl2
One mole of reagent
HC
30-
4-methylpent-1-yne
(E)-1,2-dichloro-4-methylpent-1-ene
Cl2
Second mole of reagent
1,1,2,2-tetr

Ans:

Thus, the product formed when one mole of reactant (Cl2){\rm{(C}}{{\rm{l}}_{\rm{2}}}) used is,

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