1. Formula mass of BaSO4 = (atomic mass of barium + atomic mass of sulphur + atomic mass of four oxygen atom)
= {137.327 + 32.065 + (15.999 * 4)}
= 233.388 g/mole
2. Formula of sodium nitrate is NaNO3
Molar mass of sodium nitrate = {23 + 14 + (16*3)} = 85 g/mole.
Therefore, in 85 gm sodium nitrate there is 48 g oxygen present by mass.
Percentage of oxygen present by mass in NaNO3 is
= (48 * 100) / 85
= 56.47 %
1. Calculate the formula mass for BaSO4 2. What is the percent by mass of oxygen in sodium nitrate?
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10.1 Precipitation of Barium Sulfate-Pre-Lab Questions Name Date: Instructor 1. Calculate the formula weight of BaSO4.(Enter unit as g/mol.) 2 What mass of BasO4 is presont in 40.0 mL of a 0.65 M solution? 3. What is the formula weight of Na SO? (Enter unit as g/mol.) 4. What mass of Na SO4 is present in 100.0 mL of a 0.35 M solution? 5. What is the formula weight of BaC2? (Enter unit as g/mol.) 6. You mix 6.0 mL...
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