Question

A string is wrapped around a uniform solid cylinder of radius 4.60 cm, as shown in the figure. The cylinder can rotate...

A string is wrapped around a uniform solid cylinder of radius 4.60 cm, as shown in the figure. The cylinder can rotate freely about its axis. The loose end of the string is attached to a block. The block has mass 19.6 kg, and the cylinder has mass 12.3 kg.

a) Find the magnitude α of the angular acceleration of the cylinder as the block descends.

b)What is the acceleration of the block?

c)What is the tension in the string?

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Answer #1

Applying newton's 2nd law of motion on the block,
a = mg-T
19.6*a = 192.08 - T ------------- (1)
Applying torque on wheel, τ = Iα

TR = 1/2MR^2*a/R

∴ T = 1/2*12.3*a

      T = 6.15*a ------------ (2)

substituting equation (2) in (1),

a = 7.459 m/s^2 and T = 45.875 N

the acceleration of the block is 7.459 m/s^2 and the tension in the string is 45.875 N.

(a) the angular acceleration of the cylender , α = a/R = 7.459/4.60*10^-2 m

∴ α = 162.15 rad/s

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