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Jerry forgot to record the actual molar concentration of the standard HCL solution ( which was actually 0.044M), However...

Jerry forgot to record the actual molar concentration of the standard HCL solution ( which was actually 0.044M), However to complete the calculations quickly the 0.05 M concentration was used. Will the reported molar solubility of the Ca(OH)2 be too high or too low? Explain.
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Answer #1
Ca(OH)2 + 2HCl ----> CaCl2 + 2H2O
According to the balanced equation ,
2 moles of HCl requires for 1 mole of Ca(OH)2
Since Molarity , M = no.of moles / Volume
---> No.of moles is directly proportional to Molarity of the solution
So when we use more value of the concentration instead of actual values the Molarity calculated for Ca(OH)2 is more
Which results in high solubility of Ca(OH)2
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