Question

Calculate the pH of each solution.

Part A) [OH-] = 9.9x10^-7 M

Part B) [OH-] = 3.6x10^-8 M

Part C) [OH-] = 7.2x10^-11 M

Part D) [OH-] = 9.5x10^-2 M

My Delve - Google Dr. < Chapter 14 HW Exercise 14.73 Calculate the pH of each solution Part A (OH) = 9.9x10-7M Express your answer using two decimal places. N AEV O Submit Request Answer Part B [OH - 3.6x10-M Express your answer using two decimal places. 0 AED + O2 ? Submit Pequest Answer

Answer 1

A)

Given:

[OH-] = 9.9*10^-7 M

use:

pOH = -log [OH-]

= -log (9.9*10^-7)

= 6.00

use:

PH = 14 - pOH

= 14 - 6.00

= 8.00

Answer: 8.00

B)

Given:

[OH-] = 3.6*10^-8 M

use:

pOH = -log [OH-]

= -log (3.6*10^-8)

= 7.4437

use:

PH = 14 - pOH

= 14 - 7.4437

= 6.5563

Answer: 6.56

C)

Given:

[OH-] = 7.2*10^-11 M

use:

pOH = -log [OH-]

= -log (7.2*10^-11)

= 10.1427

use:

PH = 14 - pOH

= 14 - 10.1427

= 3.8573

Answer: 3.86

D)

Given:

[OH-] = 9.5*10^-2 M

use:

pOH = -log [OH-]

= -log (9.5*10^-2)

= 1.0223

use:

PH = 14 - pOH

= 14 - 1.0223

= 12.9777

Answer: 12.98