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calculate the Gibbs free-energy change for the following reaction at 298 k if the partial pressure of each is 0.10 atm a...

calculate the Gibbs free-energy change for the following reaction at 298 k if the partial pressure of each is 0.10 atm and the Gf of NO and NOBr are 86.55 KJ/mol and 82.4 KJ/mol respectively.

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Answer #1

Equilibrium equation: 2NO(8) + Brz(8) 2 2NOBr (8) AC = [(2xACE NOR) - (2x4G(10) + 1xACC)]kJ/mol = ({ 2x82.4)-(2x86.55 + 1x0))

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