Question

Complete this table of values for four aqueous solutions at 25 °C. (oh] PH POH Given: Number Number Number Solution A: 6.1 * 10 - 13 M M Number Given: Number Number Solution B: 6.2 x 10-6 Number Number Given: Number Solution C: 5.66 Number Number Number Given: Solution D: 3.64

Answer 1

Solution A : [H+] = 6.1 x 10-13 - Now, we know that, - [H+] x [ 0H-] = 10-14 a [ot - = - 100 - 6.18 10-13 = 164 x 10-2 M pH = -log [ht] = -log (6.18 10-13) = 12:2] & port = 14- pH = 14-12-2 = 1.80 solution Bi Given, rot-] = 6.2 x 10-6 M . [H+] - 10-14 6.2 x 10-6 = 1.68.10-9]

Now, pont = – log (6.2 x 10-6) = 5.21 pH = 14 - pon = 14- 5.21 = 8.79 solution C : Given, pH = 5.66 a-log [H +] = 5.66 a log [ H+] = – 5.66. a (H+] = 10-5.66 = 2.2 x 10-6 M Thus, [ht] = 2.2 x 10-6 M [OH-] = 2 200 1 800 h = 14.5 X10-9

pot = 14- pH = 14-5-66 = 18.34 Solution D : Given, post = 3.64 a - log [ost-] = 3.64 " [ost-] = 10 -3.64 = 2.3x10-4. [ost-] = 12.3x10-4 m - [**] - 29- = 4.3 x 10-") M - pH = 14 - pon = 14- 3.64 10.4
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