A <—> 3B
3.80 0 (initial)
3.80-x 3x (at equilibrium)
Kc = [B]^3/[A]
9.91*10^-6 = (3x)^3 / (3.80-x)
Since Kc is small, x would be small
9.91*10^-6 = (3x)^3 / (3.80)
(3x)^3 = 3.77*10^-5
3x = 0.0335
x = 0.0112
[B] = 3x = 0.0335 M
Answer: 0.0335 M
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