Question

A.

V9.2.6-T Question Help Treatment Placebo A study was done using a treatment group and a placebo group. The results are shown in the table. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.10 significance level for both parts. 2 In 31 40 2.36 2.61 0.95 0.57 a. Test the claim that the two samples are from populations with the same mean. What are the null and altemative hypotheses? OA. Ho: HH2 О В. Н: н 3D Hi: H22 H: 2 D. Hn: H1P2 H H2 Ос. Но: н, # z H1: HH2 The test statistic, t, is(Round to two decimal places as needed.) Enter your answer in the answer box and then click Check Answer. parts remaining Clear All Check Answer

B.

2. The test​ statistic,is ______

​(Round to two decimal places as​ needed.)

3. The​ P-value is ______

​(Round to three decimal places as​ needed.)

4. State the conclusion for the test.

________________ the null hypothesis. There ______ sufficient evidence to support the claim that those treated with magnets have a greater mean reduction in pain than those given a sham treatment.

5. Is it valid to argue that magnets might appear to be effective if the sample sizes are​ larger?

Since the ___________ for those treated with magnets is _________ the sample mean for those given a sham​ treatment, it ___________ valid to argue that magnets might appear to be effective if the sample sizes are larger.

b. Construct a confidence interval suitable for testing the claim that those treated with magnets have a greater mean reduction in pain than those given a sham treatment.

____< μ1−μ2 < ______

​(Round to three decimal places as​ needed.)

C.

D.

P.S Can you please answer part A-D. I am very sick and I can't think right now. Please help me im begging you. My assignment is due tonight and Ive been stuck in bed all week. Please help. May god bless your soul!

Answer 1

9.2.6) a)

Since it is assumed that the population variances are unequal, the t-statistic is computed as follows: t = I1 - V ni tn 2.36 -2.61 = -1.375

Answer: t = -1.38

P-value = 0.174

Correct answer: Option (A)

b)

Based on the informationa provided, we assume that the population variances are unequal, so then the number of degrees of freedom is computed as follows: df = (sini + s/n2) /n) /m2) +1 T 2+1 - 2 = 66.891 The critical value for a = 0.1 and df = 66.891 degrees of freedom is te = tı-a/2:1-1 = 1.668. The corresponding confidence interval is computed as shown below: Since we assume that the population variances are unequal, the standard error is computed as follows: se = 1 0.572 0.952 = 131 + 40 = 0.182 Now, we finally compute the confidence interval: CI = (X - X - te x se, X; - X2 +te x se) = (2.36 -2.61 - 1.668 x 0.182, 2.36 -2.61 +1.668 x 0.182) = (-0.553, 0.053)

9.2.9) a)

Since it is assumed that the population variances are unequal, the t-statistic is computed as follows: t= X X 0.48 -0.41 0.75 +1.492 = 0.174

Correct answer: t = 0.17

P-value :  p = 0.432

We accept the null hypothesis. There is no sufficient evidence to support the claim that those treated with magnets have a greater mean reduction in pain than those given a sham treatment.

b)

Based on the informationa provided, we assume that the population variances are unequal, so then the number of degrees of freedom is computed as follows: (sini + s5 n2) - 2 = 24.17 +1 + The critical value for a = 0.05 and df = 24.17 degrees of freedom is t = ta/90-1 = 2.063. The corresponding confidence interval is computed as shown below: Since we assume that the population variances are unequal, the standard error is computed as follows: = = 0.402 Now, we finally compute the confidence interval: CI = (X1 - X-te x se, X - X2 +te x se) = (0.48 -0.41 -2.063 x 0.402, 0.48 -0.41 + 2.063 x 0.402) = (-0.76,0.9)