Question

Answer both questions please

Suppose a sodium hydroxide solution is to be standardized against pure, solid, primary-standard grade KHP. If 0.4538 g of KHP requires 44.12 mL of the sodium hydroxide solution to reach a phenolphthalein endpoint, what is the molarity of the NaOH solution? Show your calculations. 5. If 36.32 mL of the NaOH solution described in question 4 was required to titrate a 5.00 mL sample of vinegar, calculate the molarity of acetic acid in the vinegar. Show your calculations.

Answer 1

4. A Suppose a Naot solution is to be standar- dined against pure, solid, primary standard KHP. Ito. 4538 g of KAP requires 44. 12 mL of the 'Naot' to reach the phenopthelein end point, what in the molarity of Naot sol. 2 The reach between kHp + NaOH in Hk Cg Hout Naot Nakeq Hy 04+H₂o. KAP (potassium hydrogen pthalate) Reaction in li ratio reaction. Molecular weigh of kHp = 204,23g. he I mor KHP = 204,23g . ao.45389 of kHp 0.4538X1 no.of moles of kHp = 204, 23 o reach 0.0022mde Imos AHP requirea Imol Naot to phenopthelein end point moy kAp - Imol Naoth require 0.0022 moy kHP - ? 0 0022 X noort moles of Naot - 0.0022 may NAOH no. of moles Now, molarity at NaoH = volume in Las

Melayity - New 0.0.2.2 mot 0, 041 0.0499M, ? 44.1 m 44.13 - 0.0441 Toot G. Ich 26.32 mL of Naot solution describe in question 4 was required to titrate a som sample of vinegar, calculate the Molarity of CHgcool. AY The reaction between Checoot and NagH is as shown below CH₂ coolt & NaoH CH ₂ Coonat H₂o The reaction in 1:1 ratio reaction of thin reaction calculated by the formula with the help of given data molarity following Here Mi = molarity of caz cooh & volume of CH₂coolt m, & no. of moles of CH CoolH Man Molarity of Naot V = vol, of Nach & no. orf moses ort Haath

Here MF 9 M₂ = 0.0499m V = 5.0 m2 Ver toda na = 1 TH ?* 5.0 0.0499 x 36.32 + B ated Mon itoat 0.0499'x 36.32_WAL som 1.8124 ) OH (tolog H ote : 5.0 ? P ros 0.3625" Cos 14 P.