

The reason why the system is not able to evaluate the integral is that the system dynamics are unstable and the response is growing exponentially, evident from the simulation that I have carried out. The response is plotted below.

From the above response, it is observed that the system is unstable.
I have simulated the same system with a slight modification to the dynamics by replacing the positive sign with a negative sign before the second term of dxdt_2 (i.e. - 61.25). The code is given below with the response.
clc;
close all;
clear all;
t = 0:0.001:30;
initial_x = 0;
initial_dxdt = 0;
[t,x] = ode45(@rhs,t,[initial_x initial_dxdt]);
plot(t,x(:,1));
xlabel('t');ylabel('x');
function dxdt = rhs(t,x)
dxdt_1 = x(2);
dxdt_2 = -50*x(2) -
61.25*((1-cos(4*pi*10*t))/2*(47380*x(1)^3-7428*x(1)^2+366*x(1)-7));
dxdt = [dxdt_1 ; dxdt_2];
end
The stable response is plotted below.

I'm trying to solve this problem by using matlab. But I don't know reason why I can't get the solutions. I w...
I'm trying to solve this differential equations by using
matlab. But I don't know the reason why I can't get the solutions.
I've attached matlab code and few differential equation. Please
find a the way to solve this problem.
second oder ode2.m x+ function, second-oder-ode2 t-0:0.001:30 initial-x = 0; initial-dxdt = 0: lt.影=ode45( @rhs, t, [initial.x initial.dxdt ] ); plot(t.(:,1l): xlabel( t); ylabel(x): 申 function dxdt=rhs( t, x) dxdt-1 =x(2); dxdt-2 (-50 x(2)+61.25+((1-cos(4 pi 10 t))/2) (47380 x(1)-3-7428 x(1) 2...
I'm
trying to solve this differential equations by using matlab and
I've got a plot from the code attached. But I wanna get a plot of
completely sinusoidal form. If I can magnify the plot and expand
x-axis, maybe we can get the sinusoidal form. So help me with this
problem by using matlab. Example is attached in below. One is the
plot from this code and another is example.
function second_order_ode2
t=[0:0.001:1];
initial_x=0;
initial_dxdt=0;
[t,x]=ode45(@rhs,t,[initial_x initial_dxdt]);
plot(t,x(:,1))
xlabel('t')
ylabel('x')...
I'm
trying to solve this differential equations by using matlab and
I've got a plot from the code attached. But I wanna get a plot of
completely sinusoidal form. If I can magnify the plot and expand
x-axis, maybe we can get the sinusoidal form. So help me with this
problem by using matlab. Example is attached in below. One is the
plot from this code and another is example.
function second_order_ode2
t=[0:0.001:1];
initial_x=0;
initial_dxdt=0;
[t,x]=ode45(@rhs,t,[initial_x initial_dxdt]);
plot(t,x(:,1))
xlabel('t')
ylabel('x')...
MATLAB code for a double pendulum. Please explain each lines for these codes pls. ---------------------------------------------------------------------------- clc close all clear all %---------Parameters------------------------------------------------------ L1=1; L2=1 ; M_1=2 ; M_2=1; G=9.8; %---------initial condition----------------------------------------------- tspan=30; theta1=3; theta1_prime=0; theta2=2.5; theta2_prime=0; y0=[theta1 theta1_prime theta2 theta2_prime]; [t,y]=ode45(@pend, [0 ,tspan],[ 3 0 2 0]); %---position of mass 1 and mass 2---------------------------------------- x1=L1*sin(y(:,1)); y1=-L1*cos(y(:,1)); x2=L1*sin(y(:,1))+l2*sin(y(:,3)); y2=-L1*cos(y(:,1))-l2*cos(y(:,3)); %------visualizing the result--------------------------------------------- figure(1) plot(x1,y1,'linewidth',2) hold on plot(x2,y2,'r','linewidth',2) h=gca; get(h,'fontSize') set(h,'fontSize',14) xlabel('X','fontSize',14); ylabel('Y','fontSize',14); title('Chaotic Double Pendulum','fontsize',14) fh = figure(1); set(fh, 'color', 'white'); figure(2)...
PLEASE HELP SOLVE WITH MATLAB LANGUGE.
Below are hints to the problem. THANKS A LOT!!
2 Coriolis Force In a rotating frame-of-reference,the equations of motion of a particle, written in co- ordinates fixed to the frame, have additional terms due to the rotation of the frame itself Consider such a rotating frame, with its origin at the center of rotation.In these coor- dinates, the equations of motion for a point-mass subjected to forces F, and F S m, are F(0...
How can I get my while loop to run until my condition in my if statement is met? (In MATLAB) clc%clears screen clear all%clears history close all%closes all files format long %Euler's Method %Initial conditions and setup %Projectile motion x=3;%randi(3); y=3;%randi(3); figure('color','white'); plot(x,y,'bo'); hold on wind = (-10 + 20*rand(1)); fprintf('The wind speed is %2.2i\n',wind); v0= input('Initial velocity(m/s): '); a= input('Angle of projection(in degrees): '); a=a*pi/180; h=.01; cd=.1; %cdy=.1; %cdx=(rand*2-1)/2; %cdy=(rand*2-1)/2; m=1.5; g=9.8; %acceleration due to gravity in m/s^2 %td=2*v0*sin(a)/g;...
I have all of the answers to this can someone just actually
explain this matlab code and the results to me so i can get a
better understanding?
b)
(c) and (d)
%% Matlab code %%
clc;
close all;
clear all;
format long;
f=@(t,y)y*(1-y);
y(1)=0.01;
%%%% Exact solution
[t1 y1]=ode45(f,[0 9],y(1));
figure;
plot(t1,y1,'*');
hold on
% Eular therom
M=[32 64 128];
T=9;
fprintf(' M Max error \n' );
for n=1:length(M)
k=T/M(n);
t=0:k:T;
for h=1:length(t)-1
y(h+1)=y(h)+k*f(t(h),y(h));
end
plot(t,y);
hold on
%%%...
the code in the photo for this I.V.P
dy/dx= x+y. y(0)=1
i need the two in the photo
thank you
New folder Bookmarks G Google dy/dx x+y, y(0)=1 2 h Exact Solution 1.8 Approximate Solution Mesh Points 1.6 -Direction Fied 1.4 1.2 1 0.8 04 0.2 0.3 0.1 0 X CAUsersleskandara\Desktop\New folder emo.m EDITOR PUBLISH VEW Run Section FILE NAVIGATE EDIT Breakpoints Run Run and FL Advance Run and Advance Time BREAKPOINTS RUN 1 - clear all 2 clc 3-...