Electrons have half integral spins therefore they are considered as fermions. And for fermions , total wavefunction have to be anti symmetry. ( Pauli’s principle)
$ ( considering it as psi here )
condition for symmetric wavefuncion is $(1,2)= $(2,1)
Condition for antisymmtric is $(1,2) = -$(2,1).
In above given first wavefunction, alpha(1) beta(2) on spin interchanging transforms into alpha(2)beta(1). And it does not satisfy the condition of antisymmetric wavefunction.
In second wavefunction, alpha(1)beta(2) + alpha(2)beta(1) on spin interchanging became alpha(2)beta(1) + alpha(1)beta(2). And here it satisfy the condition of symmetric wavefuction
In third wave function, alpha(1)beta(2)-alpha(2)beta(1) on spin interchanging became alpha(2)beta(1)-alpha(1)beta(2).
alpha(1)beta(2)-alpha(2)beta(1) = -(alpha(2)beta(1)-alpha(1)beta(2))
this satisfies the condition of antisymmetric wavefunction to be physically valid for fermions.
Two-electron system. (A) Which of the following are physically valid wavefunctions for a two-electron system such as th...
1. (a) (10 pt) Which of the following wavefunctions CAN be a valid total wavefunction for the excited electronic state of He: 2p13d1 with the total electron spin in the triplet state (25+1 = 3), where N is the normalization constant. Explain your choice. (i) NW2p(1)3d(2) [0(1)(2)-6(1)a(2)] (ii) N [42p(1)93a(2) - za142p(2)] [a(1)B(2)+B(1)a(2)] (iii) N (42p(1)43a(2) + Y3d(1)420(2)) [a(1)$(2)-B(1)a(2)] (iv) N (42p(1)^3a(2) - 43a(1)#2p(2)] a(1)a(2) (b) (10 pt) Determine the normalization constant N in the following wavefunctigo: N [Uzo(1)3d(2) W3d(1)42p(2))...