Question

Please explain step-by-step. I'm totally lost here!
thanks in advance.

To determine the kinetic characteristics of an enzyme you used 1 nmol/L of enzyme in a series of assays where you measured the rate of reactions as you varied the concentration of substrate in each assay (Table A). Estimate from a Michaelis-Menten plot approximate values for Vex K Ka and the specificity constant for this enzyme and substrate. Table 1. [51 (M) v (nmol/L/min) 50 ujurmount) Estimated: 100 200 250 150 [s] (umoVL) V max Msi__ K, M Kot Spec const Mis-1

Answer 1

The plot of v vs. s is shown below

V vs. [s] curve v/ Lumol/L/min 50 200 250 100 150 [s] / umol/L

We know from michadi menten equation va Vmax [571 -Km 4 cs] Km is the substrate oncenhationat Which the rate is half of Vmax. the changes of data points in the final three points are in single digit and it looks like the Vmax Value Shond not differ much from 150 but will have little but hisher value from 150. Again Km Vox if we consider the I Vmax value to be half of 1.50 that is 150 = 75 then the error in the calculation would not be wrong by a great extent; since the Vimax should be in near but above value of 150. The numerical Value of kom is equants the substrate concentration at which mal is found. This approximately the km is. Considered as 20 um (where v=75). for the final data point [s] = 200 um v= 150 umol/l/min орох Km = 2 AM

This Vimax & [5] Km+CS] Vmaxx 200 mm (20+200) uh 150 uh um.min. Vmax = 150 x 220 200 loma l = 165 umoliti mint = 165 um/min IMM = 10om; I min = 605 = 165T10% ostur Vmax = 2.75×106 mist (answers

Now Consider Vinear 165 um/min Vmax CS km tes] Since Vmax = 165 mm/min, the Km Should have numerical value where the substrate concentration is = 165 unmin = 82.5 ummin The nearest Value for the value of 82.5 um/min from the data point is fummin There the c5= 20 um a put these values in the above ea Vm x 20 м - = 75 um/min . (Km +20) um in (Km +20) um = 165x20 umsmin um 25 unnin (km +200 um = 44 mm 5 km - 24 um farw Thou, am 24x10 Km =24x106m answer

Keat & Vinax 67. - Where CET is the initial concentration of enzynne. Inmol 163 umor DE. - Innoy = 105 umol/L Keat = 165 umbl 14 min Tom underla = 165x1873 min - 165*103 , = 2.75x10², Canswer) 60 Spec const & Keat. km = 275x103 gel 24 um = 2.75×103 srl 24x106m = 1:145x108 milgri Canswer