Question

13. A balloon has a volume of 1.20 liters at 24.0°C. The balloon is heated to 48.0°C. Calculate the new volume of the balloon. A) 1.20 L B) 1.30 L C) 1.70 L D) 2.10 L E) 2.40 L

Answer 1

c + 273.15 Final conditions Initial conditions V1.20L T = (24.0 + 272.15) TL 291. ISK T = 48.0+ 273.15)k 321.15k 7 Relation between V and TO = V.T2 & ₂ = (1.20L ) (321. Isklon 297. 15k => 1.20 L - 1.30L B 1. 30 L