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A high-speed machine requires the number of parts to be counted before changing the dies for the next part. The number o...

A high-speed machine requires the number of parts to be counted before changing the dies for the next part. The number of parts is 83,200. Construct a counter program that will operate a buzzer and stop the process when the number of parts is reached. [Note: Make sure that you use values which are not out of range.]

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Answer #1

I m writing the program for assembly level language of 8051

ORG 0000H

MOV R1,#2

RPT: MOV TMOD,#15H ;TIMER 1 AS TIMER AND TIMER 0 AS COUNTER

SETB P3.4 ;MAKE IT AS AN INPUT PORT

AGN: MOV TL0,#00H ;SET VALUES

MOV TH0,#00H

SETB TR0 ;START COUNTER

    MOV R0,#28 ;TAKING THE TIME INTERVAL OF 1 SEC

AGAIN: MOV TL1 ,#00H

MOV TH1,#00H

SETB TR1 ;START THE TIMER

BACK: JNB TF1 ,BACK

CLR TF1

CLR TR1

DJNZ R0,AGAIN

MOV A,TL0

MOV P2,A

MOV A,TH0

MOV P1,A

CJNE TL0,#80H,HERE

CJNE TH0,#A2H,HERE1

DJNZ R1, AGN

SETB P3.7 ;BUZZER

CLR P3.4 ;STOP THE MACHINE

HERE: SJMP RPT

HERE1:SJMP RPT

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