Question

Example 5 Nuclear Incident A nuclear incident has exposed a 70kg worker to 1 Ci of 2 MeV photons for 1 minute. Assuming that all the energy of absorbed photons is deposited in the body with uniform distribution, what absorbed dose of radiation has the worker suffered? What effective dose? What would have been his effective dose if the exposure has been concentrated entirely in his stomach (mass 0.5kg)?

Answer 1

ount of energy absorbed by the person-E E-2MeV × 1.602e-19-ー×1.0× 3.7e+10-ecay x60sec =0.71 137J sec worker weight -70kg 0.71137 dosage0.0101621.0162 rad kg conversion 1Gy-1.0-100rad effective dosage in rem-numberof rad x RBE (RBE of photons -1.0) (RBE-Relative Biological Effectiveness) -1.0162 REM 1.0162e-02Sv (1Sv-100REM) .4227-= 1.4227e +02 rad 1 0.5kg if the total energy absorption takes placein this stomach.dosage - kg effective dosage in rem -number of radx RBE (RBEof gamma .0) (RBE Relative Biological Effectiveness) - 1.4227e 02 REM 1.4227 Sv 1.4227 Sv