Question

A robotic rover on Planet Z finds a spherical rock with a diameter of 12 cm and a specific gravity of 2.32. The rover picks up the rock and lifts it 20 cm straight up. If the robot’s lifting arm has an efficiency of 25%, required 10 seconds to raise the rock and used exactly 1 Watt of power, what is the acceleration due to gravity on Planet Z?

Answer 1

Rock : R=6cm D=12cm S4=2.32 colume proase = 4 7 R² = 9040778 cm3 mass - VX SG = 2099119 m=200991kg wi let gravity = 9 h= 20cm=0.am efficiency = 150). 20-25 WD = mgh time = 10 sec. px 0.25 = mgh 1x0.25 = 2.099 x 9x0.2. 10 19 = 5.95 m28?)